t^2+2t=44

Solution for t^2+2t=44 equation:

t^2+2t=44

We move all terms to the left:

t^2+2t-(44)=0

a = 1; b = 2; c = -44;
Δ = b2-4ac
Δ = 22-4·1·(-44)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6\sqrt{5}}{2*1}=\frac{-2-6\sqrt{5}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6\sqrt{5}}{2*1}=\frac{-2+6\sqrt{5}}{2}
$